4.9x^2-35x+50=0

Solution for 4.9x^2-35x+50=0 equation:

4.9x^2-35x+50=0

a = 4.9; b = -35; c = +50;
Δ = b2-4ac
Δ = -352-4·4.9·50
Δ = 245
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-\sqrt{245}}{2*4.9}=\frac{35-\sqrt{245}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+\sqrt{245}}{2*4.9}=\frac{35+\sqrt{245}}{9.8}
$